SOLUTION: Solve for y in the equation
3(y^2 +3)= 28y
Algebra.Com
Question 824355: Solve for y in the equation
3(y^2 +3)= 28y
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
3(y^2+3)= 28y
3y^2+9 = 28y
3y^2+9-28y = 0
3y^2-28y+9 = 0
Use the quadratic formula to solve for y
Plug in , ,
or
or
or
or
The two solutions are
or
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