SOLUTION: [ write an equation for the line that is parallel to the given line and that passes through a given [point]. ]
y=-2/3x+12 (5,-3)
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Question 817528: [ write an equation for the line that is parallel to the given line and that passes through a given [point]. ]
y=-2/3x+12 (5,-3)
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
given:
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y = (-2/3)x + 12
(5,-3)
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parallel lines have equal slopes.
so the slope of the new line is the same as the slope of the given line: -2/3
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use the point-slope form:
point = (5,-3)
slope = (-2/3) = -0.666666...
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to solve the linear equation, plug this:
5, -3, -0.666666
into the "Point-Slope form: x1 y1 m" input box of this solver:
https://sooeet.com/math/linear-equation-solver.php
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slope = -2/3
y-intercept = 0.33333 = 1/3
---
Answer:
the slope-intercept form:
y = -2/3x + 1/3
---
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https://sooeet.com/math/quadratic-formula-solver.php
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