SOLUTION: 10x^4-9x^2+2=0 I set x^2=u I got u=2/5 u=1/2 when I use the square root property x^2= ±√(2/5) and x^2=±√(1/2), and the math lab says is wrong. Why???

Algebra.Com
Question 814150: 10x^4-9x^2+2=0
I set x^2=u
I got u=2/5
u=1/2
when I use the square root property x^2= ±√(2/5) and x^2=±√(1/2), and the math lab says is wrong. Why???

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x^2=u
10u^2-9u+2=0
x^2=2/5 not +-sqrt(2/5)
[x=+-sqrt(2/5) we don't need to know this; we never use it.]
x^2=1/2 not +-sqrt(1/2)
[x=+-sqrt(1/2) we don't need to know this; we never use it.]
check
10*1/4-9* 1/2+2=0
2.5-4.5+2=0
0=0
ok
check
10*4/25-9*2/5+2=0
40/25-18/5+2=0
8/5-18/5+10/5=0
0=0
ok



RELATED QUESTIONS

(3+ √x)^2 + 3(3+√x)-10=0 u = (3+√x) u^2= (3+√x)^2 u^2 + 3u -... (answered by Fombitz)
Solve for x. x^4 - 5x^2 -12 = 0 I can write x^4 like this: (x^2)^2. Let u = x^2. (answered by ikleyn,greenestamps)
are my domains correct? √(x-5)^2: [5,inf) √(x^2-5): [5,inf)... (answered by MathLover1)
What is the solution for this equation? I know i had to use the u, u^2 formula for this. (answered by Alan3354)
Can someone please help? Expand (x-2√y)(x+2√y) and simplify. Assume y... (answered by Alan3354)
5-2i√(5) and... (answered by Alan3354)
Find all points having an​ x-coordinate of 2 whose distance from the point... (answered by josgarithmetic)
√(X-2)=... (answered by funmath)
Suppose cos(u)= 5/13, and sin(u) is negative. Find sin(u-pi), cos(u-pi), sin(u-pi/2),... (answered by jim_thompson5910)