SOLUTION: Solve for b. a = 1/2 bc^2
This is really strange and I am not sure what to do? Where are all the numbers?
Algebra.Com
Question 81284: Solve for b. a = 1/2 bc^2
This is really strange and I am not sure what to do? Where are all the numbers?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve for b. a = 1/2 bc^2
-----------
Comment: When you are studying algebra letters ARE numbers.
----------
Your Problem:
a = (1/2)bc^2
Multiply both sides by 2 to get:
2a = bc^2
Divide both sides by c^2 to solve for "b":
b = (2a)/b^2
=============
cheers,
Stan H.
RELATED QUESTIONS
Solve the equation for x:
x^2+4x+4=7
I am not sure where to start with this one. It is (answered by checkley71)
I'm not sure where to start with this proof i'll show you what I have so far but i am not (answered by elima)
Okay, I am taking Algebra again after a 10 year lapse. The following question is really... (answered by edjones)
I am having trouble with two equations - solving for variables...
A = P+PRT... (answered by stanbon)
hello, i am new to this online help. I really do not know where consecutive... (answered by Alan3354)
Not really sure on what I'm suppose to do. This is all I know.
PRACTICE: Use factoring (answered by Alan3354)
PLEASE HELP ME!!!!
I need help because i am confused i am not getting this please... (answered by stanbon)
A student is asked to solve b^2+b^2=c^2 for a and gives the following solution. Assume... (answered by Alan3354,Edwin McCravy)
1. Verify the identity.
sin(9𝑥)+sin(3𝑥)/cos(9𝑥)+cos(3𝑥)=tan(6𝑥)
2. (answered by Alan3354)