SOLUTION: Solve for n. R=Pi/1-(1+i)^-n

Question 812728: Solve for n.
R=Pi/1-(1+i)^-n

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve for n.
R=Pi/1-(1+i)^-n
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1 - (1+i)^-n = pi/R
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(1+i)^-n = 1-[pi/R]
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(1+i)^n = 1/[1-(pi/R)]
n*log(1+i) = -log[1-(pi/R)
----
n = -log[(R-pi)/R]/log(1+i)
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Cheers,
Stan H.
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