SOLUTION: can someone check this for me? I have to factor completely. x^2+9x+18 18+9x+x^2=0 (6+x)(3+x)=0 6+x=0 6+-6+x=0+-6 0+x=0+-6 x=0+-6 x=-6

Algebra ->  Equations -> SOLUTION: can someone check this for me? I have to factor completely. x^2+9x+18 18+9x+x^2=0 (6+x)(3+x)=0 6+x=0 6+-6+x=0+-6 0+x=0+-6 x=0+-6 x=-6      Log On


   



Question 81245: can someone check this for me?
I have to factor completely.
x^2+9x+18
18+9x+x^2=0
(6+x)(3+x)=0
6+x=0
6+-6+x=0+-6
0+x=0+-6
x=0+-6
x=-6

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You're on the right track. You just need to solve for the other value of x

Set 3%2Bx equal to zero

3%2Bx=0

x=-3 Subtract 3 from both sides

So the solution is (adding to what you have)

x=-6 or x=-3