SOLUTION: Two trains (local and express) start at the same time going from A to B
The express train travels 120km and averages 20km per hour faster than the local train. If the local train
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Question 807588: Two trains (local and express) start at the same time going from A to B
The express train travels 120km and averages 20km per hour faster than the local train. If the local train still has 80km to go when the express train arrives at B, what is the average speed of the express train?
D=RT
express train 120km, rate is x+20...time is 120/x+20
local train is 40km..rate is x...time is 40/x
i think im off to the right start...help!
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two trains (local and express) start at the same time going from A to B
The express train travels 120km and averages 20km per hour faster than the local train. If the local train still has 80km to go when the express train arrives at B, what is the average speed of the express train?
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Express Train DATA:
rate = 120 km/hr ; time = t hrs ; distance = 120t km
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Local Train DATA::
rate = 100 km/hr ; time = t hrs ; distance = 100t km
------
Equation:
express dist - local distance = 80 km
----
120t - 100t = 80
20t = 80
time = 4 hrs
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Ans: Average speed of the express train = 120 km/hr
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Note: Are you sure you posted the right question for the problem?
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Cheers,
Stan H.
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Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Two trains (local and express) start at the same time going from A to B
The express train travels 120km and averages 20km per hour faster than the local train. If the local train still has 80km to go when the express train arrives at B, what is the average speed of the express train?
D=RT
express train 120km, rate is x+20...time is 120/x+20
local train is 40km..rate is x...time is 40/x
i think im off to the right start...help!
Yes, You are!!
Anyway, since you're seeking the express train's speed, I'd let that speed be x, which makes the local train's speed, x - 20. You then equate their times: . Solve this for x and you'll have the express train's speed.
Express train's speed: km/h
You can do the check!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com. Further help is available, online or in-person, for a fee, obviously.
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