SOLUTION: Solve the system by addition.
2x + 4y = 3
4x - 2y = 1
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Question 80663: Solve the system by addition.
2x + 4y = 3
4x - 2y = 1
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
QUESTION:
Solve the system by addition.
2x + 4y = 3
4x - 2y = 1
ANSWER:
Name the given equations as follows:
2x + 4y = 3 -----------------(1)
4x - 2y = 1 -----------------(2)
Multiply the second equation with 2.
==> 2(4x - 2y ) = 2* 1
==> 2*4x - 2*2y = 2
==> 8x - 4y = 2 --------------(3)
Now consider equation (1) and (3)
2x + 4y = 3 -----------------(1)
8x - 4y = 2 -----------------(3)
Add (1) and (3)...then we have,
2x + 4y + 8x - 4y = 3 + 2
==> 2x + 8x + 4y - 4y = 5
==> 10x + 0 = 5
==> 10x = 5
Now divide both sides of the equation by 10.
==> 10x/10 = 5/10
==> x = 1/2
Now substitute the value x = 1/ in any of the given equations.
Let's take equation (1).
==> 2*(1/2)+ 4y = 3
==> 1 + 4y = 3
Subtract 1 from both sides of the expression.
==> 1 + 4y -1 = 3 - 1
==> 4y = 2
Divide both sides of the equation by 4.
==> 4y/4 = 2/4
==> y = 1/2
So the solution for the given pair of equation is
x = 1/2 and y = 1/2.
Hope you understood.
Regards.
Praseena.
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