SOLUTION: 16: 8(c3 - c) = c (6c + 1)

Algebra.Com
Question 80585: 16:
8(c3 - c) = c (6c + 1)

Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!
8(c^3-c)=c(6c+1)
8c^3-8c=6c^2+c
8c^3-6c^2-9c=0
c(8c^2-6c-9)=0
c(4c+3)(2c-3)=0
c=0 answer
4c+3=0
4c=-3
c=-3/4 or -.75 answer
2c-3=0
2c=3
c=3/2 or 1.5 answer.

RELATED QUESTIONS

8(c3 - c) = c (6c + 1) or 8(c^3-c) = c... (answered by jim_thompson5910)
16: 8(c^3 - c) = c (6c +... (answered by stanbon)
(2x + 1)C3 - (2x-1)C3 - 2(xC2) NOTE: C stands for... (answered by stanbon)
factor the trinomial... (answered by richwmiller,MathTherapy)
(-c3)(c) (negetive c... (answered by copy_paste)
6c-8-2c=-16 (answered by MathLover1)
1/18c - 1/36 + 1/6c = 1/6 + c (answered by rfer)
If on an average it rains on 5 days in every thirty days, then find the probability that... (answered by user_dude2008)
please show me how to solve this problem: (C-1)-12 (C-5)6 over (C-4)0... (answered by longjonsilver)