SOLUTION: What is an expiation of a line that contains the point (-4,3) and is perpendicular to the graph of x-2y=8

Question 804039: What is an expiation of a line that contains the point (-4,3) and is perpendicular to the graph of x-2y=8
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is an equation of a line that contains the point (-4,3) and is perpendicular to the graph of x-2y=8
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Find slope of the given equation::
2y = x-8
y = (1/2)x-4
slope = 1/2
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So, slope of a perpendicular line must be -2.
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Form of desirec equation: y = mx + b
Solve for "b":
3 = -2*-4 + b
3 = 8 + b
b = -5
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Equation::
y = -2x - 5
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Cheers,
Stan H.
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