SOLUTION: how do you solve 7(3x +4)= 8(2x +5) +13

Question 79406: how do you solve 7(3x +4)= 8(2x +5) +13
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
7(3x +4)= 8(2x +5) +13 [use the distributive property to multiply]
21x+28=16x+40+13 [combine like-terms if possible]
21x+28=16x+53 [solve for the x-term]
21x-16x+28=16x-16x+53
5x+28=53
5x+28-28=53-28
5x=25
5x/5=25/5
x=5
.
check by plugging (x=5) back into the orignial eqution and solve]
7(3x +4)= 8(2x +5) +13
7[3(5) +4]= 8[2(5) +5] +13
133=133 [checks out]
RELATED QUESTIONS
7(3x + 4) + 8(2x + 5) +... (answered by funmath)

7(3x+4) = 8(2x+5) +... (answered by ptaylor)

... (answered by funmath)

7(3x + 4) = 8(2x + 5)+... (answered by stanbon)

7(3x+ 4) = 8(2x + 5) +... (answered by THANApHD)

7(3x + 4) = 8(2x+ 5) + 13 (answered by checkley75)

7(3x + 4) =8(2x + 5) +... (answered by checkley75)

7(3x+4)=8(2x+5)+13 how do I solve this problem? I have a teacher who doesn't want to help (answered by akmb1215)

HOW DO YOU SOLVE THIS 3X-5<4(3X+7-8) (answered by stanbon)