SOLUTION: Fill in the blank to complete this equation:
1+2+3+...+(n-1)+n+n+(n-1)+...+3+2+1=___________
I know your suppose to square the (n-1), but I just don't know where to even start.
Algebra.Com
Question 788956: Fill in the blank to complete this equation:
1+2+3+...+(n-1)+n+n+(n-1)+...+3+2+1=___________
I know your suppose to square the (n-1), but I just don't know where to even start.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(1+2+3+...+(n-1)+n)+(n+(n-1)+...+3+2+1)=___________
It consists of 2 same sequences
Sum of n terms
Sn = n/2(2a+(n-1)d)
a=1
d=1
n=n
sn = n/2(2+(n-1)1))
Sn = n(n+1)/2
2 Sn = n(n+1)
n(n+1)
RELATED QUESTIONS
Could someone please check my work on the following paragraph proof? This is to show why (answered by robertb)
Fill in table using the given formulas. S=n(n + 1)(2n + 1) I need to know what goes next (answered by stanbon)
Dear math teacher,
I am having difficulties with the following problem:
4 times nC2 (answered by Theo)
Evaluate:
1*1!+ 2*2!+3*3!+.....+n*n! where n is in N
I started with if
n=1 then... (answered by venugopalramana)
n!
_______
2!(n-2)!
I understand that 5! is 5*4*3*2*1
I do not understand how to... (answered by Earlsdon,stanbon)
Please help me solve this equation: 2=n-(2n+3). I need to find the value of n. The book (answered by longjonsilver,scoop,shorty33353)
PLEASE HELP ME I DONT KNOW WHAT TO DO!!!!!!... (answered by MathTherapy)
THE SUM OF THE SQUARES OF TWO CONSECUTIVE POSITIVE INTEGERS IS 41
41=n^2(n+1)^2... (answered by richard1234)
{{{ (1/2^n)+(3/2^3)+(5/2^n-3)-(82/2^n+1) }}} i have the answer which is {{{ 3/8 }}} but... (answered by ikleyn)