SOLUTION: <pre> k 3 3 - + - = - 16 4 8 </pre> 2p-56=6p 5b+22-4b=22+34b+7

Question 78801:
k 3 3 - + - = - 16 4 8

2p-56=6p
5b+22-4b=22+34b+7

Answer by mathdoc314(58) (Show Source): You can put this solution on YOUR website!
This looks like two separate answers

k     3   3    
-  +  - = -
16    4   8

Multiply through by 16 which is the l.c.d. (least common denominator, or least common multiple of 16, 4, and 8).

16k/16 + 3*16/4 = 3*16/8
k + 3*4 = 3*2
k + 12 = 6
Subtract 12 from either side
k + 12 - 12 = 6 - 12
k = -6

Second problem: 2p-56=6p
I think you want to solve for p?
Subtract 2p from each side
-56 = 6p - 2p
-56 = 4p
Divide both sides by 4
-14 = p
That is the answer.
Third problem:
I think you want to solve for b?
5b+22-4b=22+34b+7
I will tell you the steps and you see if you can do them
Step 1. On the left side you can combine 5b - 4b = (5-4)b = b
Step 2. You can cancel 22 that is simply added on both sides of the equation
Step 3. That should leave you with b = 34b + 7
Step 4. Subtract 34b from both sides. 1b - 34b = -33 b
Step 5. Divide both sides by -33. This should give you b=-33/7

RELATED QUESTIONS
5b^3+34b^2=7b (answered by Nate)

Solve for x:

   1         1          22
������� + ������� = ���������
 x - 4     (answered by AnlytcPhil)
2p-q=2
2p+3q=22

Equation 1      2p-q=2  Multiply by 3 so, 6p-3q=6
    6p-3q = 6
     (answered by checkley77)
 18        21       24
  3         9        3
  6         4        8
----... (answered by Edwin McCravy)
Combine 



4         
---       -   x^(1/3)
x^(2/3)... (answered by jim_thompson5910)
Compute the determinant
| 1  2  3  4|
| 5  6  7  8|
| 9 10 11 12|
|13 14 15... (answered by Edwin McCravy)
Can you please solve.

x  1  2  3  4 
a 18 16 14 12

a=????
Thanks Brad
 (answered by AnlytcPhil)
Let A= [0]  B=[1 2 3]  C=[-3 7]
       [-4]   [0 5 2]    [ 9 8]
       [3]    [0  (answered by Edwin McCravy)
-2(2p-4)-6p-3 (answered by jim_thompson5910)