1. Pick a letter to eliminate 2. Pick 2 equations to eliminate that letter from 3. Pick one of those equations with the third equation and eliminate that SAME letter from. 4. Solve the resulting system of two equations in two unknowns. 5. Substitute those values in one of the original equations to find the first letter eliminated. (1) -x + y + 2z = 7 (2) 2x + 3y + z = 1 (3) -3x - 4y + z = 4 1. Pick a letter to eliminate. I'll pick z 2. Pick 2 equations to eliminate that letter from I'll pick (2) and (3): (2) 2x + 3y + z = 1 (3) -3x - 4y + z = 4 I'll multiply (2) by -1 and add (3) to it -2x - 3y - z = -1 (3) -3x - 4y + z = 4 ------------------------- (4) -5x - 7y = 3 3. Pick one of those equations with the third equation and eliminate that SAME letter from. I'll pick (2) and use it with (1) to eliminate the SAME letter z (1) -x + y + 2z = 7 (2) 2x + 3y + z = 1 I'll multiply (2) by -2 and add it to (1) (1) -x + y + 2z = 7 -4x - 6y - 2z = -2 ------------------------- (5) -5x - 5y = 5 4. Solve the resulting system of two equations in two unknowns. (4) -5x - 7y = 3 (5) -5x - 5y = 5 Multiply (4) by -1 and add (5) to it: 5x + 7y = -3 (5) -5x - 5y = 5 -------------------- 2y = 2 y = 1 Substitute y = 1 in (4) to find x (4) -5x - 7y = 3 -5x - 7(1) = 3 -5x - 7 = 3 -5x = 10 x = -2 5. Substitute those values in one of the original equations to find the first letter eliminated. I'll substitute x = -2 and y = 1 in (2) (2) 2x + 3y + z = 1 2(-2) + 3(1) + z = 1 -4 + 3 + z = 1 -1 + z = 1 z = 2 (x,y,z) = (-2,1,2) Notice that different people would pick different letters and diferent equations but in the end the solutions would all be the same. Also sometimes the process can be shortened because one of the letters is already eliminated from one of the equations. But that was not the case here because all three equations cntained all three letters. Edwin