SOLUTION: Please help me .I need to fine the equation ,in standard form, with all integer coefficients, of the line perpendicular to x+2y=8 and passing through (1,-6) Thanks very muc

Question 78316This question is from textbook intermediate algebra
: Please help me .I need to fine the equation ,in standard form, with all integer coefficients, of the line perpendicular to x+2y=8 and passing through (1,-6)

Thanks very much for all your help . This question is from textbook intermediate algebra

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
X-2Y=8
2Y=-X+8
Y=-X/2+8/2
Y=-X/2+4 THIS IS THE EQUATION IN LINE FORM WHERE -1/2 IS THE SLOPE (m) & 4 IS THE Y INTERCEPT(b) OR THE POINT (0,4).
THE LINE PERPENDICULAR TO THIS LINE WILL HAVE A SLOPE OF THE NEGATIVE RECIPRICAL OF THIS SLOPE THUS THE NEW SLOPE IS 2.
NOW WE USE THIS SLOPE (m) AND THE X&Y POINTS GIVEN & SOLVE FOR THE Y INTERCEPT.
-6=2*1+b
-6=2+b
b=-6-2
b=-8 WHICH IS THE Y INTERCEPT FOR THE PERPENDICULAR LINE WITH THE EQUATION OF
Y=2X-8
NOW WE'LL PLOT THE ORIGINAL LINE (RED) AND TRHE PERPENDICULAR LINE (GREEN).
(graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -x/2 +4 and y = 2x -8).

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