Solve each of the following quadratic equations by completing the square.

 x^2-6x-3=0





      x^2 - 6x - 3 = 0



    x^2 - 6x + ___ = 3

    

    x^2 - 6x + 9 = 3 + 9



       (x - 3)^2 = 12



          x - 3 = +-



          x - 3 = +-



          x -3 = +- 2 



           x = 3 +- 2  



x = 3 + 2  or  x = 3 - 2  





 

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
 I'm just adding onto the previous poster's work...

Note: when you take a square root you get 





 (plus or minus the square root of 12)





 Add 3 to both sides



So you should have 2 answers:





 or 



Which reduce to 



 or  

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