SOLUTION: what is the quadratic equation of 8y+3y^2=35? please help!

Question 782302: what is the quadratic equation of 8y+3y^2=35? please help!
Answer by waynest(281) (Show Source): You can put this solution on YOUR website!
8y + 3y^2 = 35
3y^2 + 8y - 35 = 0
use quadratic equation to solve:
(-8 +-sqrt8^2 - 4(3)(-35))/2(3)
(-8 +-sqrt64 +420) /6
(-8 +-sqrt484) /6
(-8 +- 22) /6
(-4 +- 11) /3
x = (-4 + 11) /3 = 2.33
x = (-4 - 11) /3 = -5
RELATED QUESTIONS
PLEASE HELP ME SOLVE THIS EQUATION :... (answered by mananth)

What is the quadratic equation of 6x^2-8xy-8y^2... (answered by mananth,josgarithmetic)

what is the answer for this equation? -{4x-(3y-8x)-[8y-12x-y]} Please help me. Thank... (answered by solver91311)

This is a quadratic equation: {{{y^2+8y=0}}}. Help please? I got it... (answered by drglass)

could you please help me on this equatins ? The point (6, 2) lies on the line -x � 8y... (answered by asuar010)

Can someone please help me Find the product:... (answered by rfer)

can you please help in showing me the steps to solve this equation? thank you. The... (answered by Theo)

I am working on solving linear and quadratic equations. I need help with this problem: (answered by ankor@dixie-net.com)

If the roots of quadratic equation are -7 and -5, write the equation in ax^2 + bx + c = (answered by ewatrrr)