SOLUTION: Find the center and radius of the circle defined by the equation:
X^2+Y^2+4X-8Y+13=0
Please!! Help!
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Question 781417: Find the center and radius of the circle defined by the equation:
X^2+Y^2+4X-8Y+13=0
Please!! Help!
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You want the equation in a form, in which the center is (h,k) and radius is r. This is a Complete-the-Square problem.
The terms with x need and the terms with y need
(x+2)^2+(y-4)^2=7
Center: (-2,4)
Radius: sqrt(7)
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