SOLUTION: (3m-5)(m+7)=0 solve for m. Please. Thanks.

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Question 77918: (3m-5)(m+7)=0
solve for m.
Please. Thanks.
Found 2 solutions by bucky, Edwin McCravy:
Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!
(3m-5)(m+7)=0
.
If either of the two factors on the left side equals zero, then the left side becomes
zero. This is because multiplying anything by zero results in zero as the answer. And if
the left side is zero, then it equals the right side.
.
Just as a further example in the way of explanation, suppose (3m - 5) equals zero, then the
equation becomes 0 * (m + 7) = 0. And this means that we need to find what value of m
will make 3m - 5 equal zero. Now suppose (m + 7) equals zero. This would make the
equation become (3m - 5) * 0 = 0. Note that this equation is true because the left side
is zero (due to the multiplication by zero) and, therefore, it equals the right side.
.
So all you need to do for this problem is to set each of the factors equal and solve
for m.
.
3m - 5 = 0
.
eliminate the -5 on the left side by adding 5 to both sides to get:
.
3m = +5
.
Then solve for m by dividing both sides by 3 to get:
.
m = 5/3
.
Next, we set the other factor equal to zero:
.
m + 7 = 0
.
eliminate the + 7 on the left side by subtracting 7 from both sides to get:
.
m = -7
.
There you have it ... two values of m will satisfy the original equation. Those two values
for m are m = 5/3 and m = -7.
.
And if you substitute those two values for m into the original equation you will see
that they work.
.
Hope this helps you to understand the problem.
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!


solve for m. 
Please. Thanks.



When there is a zero on the right side,
and the left side is factored, we know
that one of those factors must be 0 in
order for their product to equal 0. Since
it could be either one of them which 
equals 0, we set each of them = 0 and
we get two possible solutions.

Setting the first factor = 0:





Setting the second factor = 0:




Edwin
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