SOLUTION: find an equation in Slope-Intercept Form of the line that goes through (8,3) and (2,-1)

Question 778130: find an equation in Slope-Intercept Form of the line that goes through (8,3) and (2,-1)
Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Distribute

Multiply

Add 3 to both sides.

Combine like terms. note: If you need help with fractions, check out this solver.

So the equation that goes through the points and is

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: Find the equation of line going through points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (8, 3) and (x2, y2) = (2, -1).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(0.666666666666667)x + (-2.33333333333333)

Your graph:

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