SOLUTION: I need help trying to solve this equation. The equation is t^2+81=0 would this be a quadratic function problem or would this be like solving a normal equation? If i solve it li

Question 771745: I need help trying to solve this equation. The equation is t^2+81=0
would this be a quadratic function problem or would this be like solving a normal equation?
If i solve it like a normal equation i keep on getting a negative under the square root sign.
how would i write the answer?
square root of -81 or square root -27 or square root +/- 27 or 81 or with the -81i
Found 2 solutions by ashin, DrBeeee:
Answer by ashin(3) (Show Source): You can put this solution on YOUR website!
t^2+81= 0
t^2= 0-81
t^2= -81
t= square root -81
t= square root (81*-1)
t= (square root 81)* (square root -1)
t= (+/-)9*i
t= (+/-)9i
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Given:
(1) or
(2)
Now take the square root of both sides and get
(3) which is has two complex roots
(4) x = {-9i,9i}
RELATED QUESTIONS
I'm trying to solve an equation I've been working on, but it's been a long time since my... (answered by longjonsilver)
I'm trying to determine a quadratic equation that exhibits such: The equation I am... (answered by stanbon)
Hello everyone,I am having some trouble solving this problem. f(t) = {{{ 5sqrt(t) -... (answered by ikleyn,greenestamps)
Please help. I need to solve this equation for t and I have no clue on how to do it. If... (answered by mananth,MathTherapy)
Hi all, I was hoping someone could show me how to solve the following quadratic equation: (answered by Edwin McCravy)
I am trying to solve this quadratic growth question. A town experiences quadratic... (answered by stanbon)
Hello again my friends. Can someone help me solve this problem ? Also I would like to... (answered by josgarithmetic)
Please help!! I need answers to the following questions, I really need to past this... (answered by sudhanshu_kmr)
I have a problem where I need to solve the equation (2/t)= (t/5t-12) and the lcd will... (answered by stanbon,ankor@dixie-net.com)