SOLUTION: PLEASE help me. I don't get it at all. I'm desperate :'( I've tried doing it so many time but I just don't get it. :'(
a9 - 1
A (a3 - 1)(a6 + a3 + 1)
B(a + 1)(a6 + a3 + 1)
Algebra.Com
Question 766755: PLEASE help me. I don't get it at all. I'm desperate :'( I've tried doing it so many time but I just don't get it. :'(
a9 - 1
A (a3 - 1)(a6 + a3 + 1)
B(a + 1)(a6 + a3 + 1)
C(a - 1)(a2 - a - 1)(a6 + a3 + 1)
D(a - 1)(a2 + a + 1)(a6 + a3 + 1)
E (a3 + a + 1)(a6 + a3 + 1)
F cannot be factored
a4 + 3a3+ 27a + 81
A (a2 + 3a - 9)(a2 + 2a + 3)
B(a - 3)(a2 + 3a + 9)
C(a + 3)(a2 + 2a + 3)
D(a + 3)(a2 + 4a + 9)
E [(a + 3)2](a2 - 3a + 9)
F cannot be factored
x8 - 16x4
A x4(x - 2)(x + 2)(x2 + 4)
B(x4 + 4x2)2
C(x4 - 4x2)2
D(x4 + 4x2)(x4 - 4x2)
E x4(x4 - 16)
F cannot be factored
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
There are special products that are probably shown as formulas in your textbook, and are useful in factoring. Some examples:
Square of a binomial:
and
Cube of a binomial:
and
Difference of squares:
Sum and difference of cubes:
and
There is also taking out a common factor (if there is one), and factoring by parts (if applicable).
=
A
E is a factorization, but is not a factorization, because you can factor further
F cannot be factored
can be factored by parts:
At this point, you factor as a special product and get
E
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