SOLUTION: Please PLEASE help me. :'( :'( I don't understand it at ALL. :'( x4 + 2x3 - 8x - 16 A (x + 2)(x2 + 2x + 4) B(x - 2)(x2 + 2x + 4) C(x

SOLUTION: Please PLEASE help me. :'( :'( I don't understand it at ALL. :'( x4 + 2x3 - 8x - 16 A (x + 2)(x2 + 2x + 4) B(x - 2)(x2 + 2x + 4) C(x - 2)(x + 2)(x2 + 2x + 4) D(x + 2)

Question 766753: Please PLEASE help me. :'( :'( I don't understand it at ALL. :'(

x4 + 2x3 - 8x - 16
A (x + 2)(x2 + 2x + 4)
B(x - 2)(x2 + 2x + 4)
C(x - 2)(x + 2)(x2 + 2x + 4)
D(x + 2)(x2 + 4x + 8)
E (x2 + 4x - 4)(x2 + 2x + 4)
F cannot be factored

x3 - 12x2 + 48x - 64
A (x - 4)(x + 4)2
B(x-4)3
C(x + 4)3
D(x + 4)(x - 4)2
E (x - 4)(x2 + 2x + 1)
F cannot be factored
-2w4 + 1250
A -2(w2 + 25)
B(w - 5)(w + 5)(w2 + 25)
C-2(w - 5)(w2 + 25)
D-2(w - 5)(w - 5)(w2 + 25)
E -2(w - 5)(w + 5)(w2 + 25)
F cannot be factored

Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
In saying "x3 - 12x2 + 48x - 64", you really mean this: .

You need proper text usage and tags for making the typesetting or rendering.

None of the choices shown for that one are correct but the polynomial IS factorable. Try guessing at some linear binomial as a divisor and do polynomial division ---------- I should not say that, since you are probably only in Algebra 1 and have not dealt much with root finding and such. Even so, polynomial division is actually easier than long division on base ten numbers.

Anyway, looking at the particular polynomial, I guessed that either x-4 or x+4 could be a possible factor, so I tried polynomial long division. The factor which worked was x-4. The correct factorization that you are looking for is NOT shown in your list of choices.

I found this:

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