SOLUTION: Please please please help me :'(
x9 + 1
A (x + 1)(x2 - x + 1)(x6 - x3 + 1)
B(x3 + 1)(x6 + 1)
C(x + 1)(x2 - x + 1)(x3-1)2
D(x + 1)3(x2 - x + 1)3
E (x3 + 1)(x6 - x3 + 1)
Algebra.Com
Question 766752: Please please please help me :'(
x9 + 1
A (x + 1)(x2 - x + 1)(x6 - x3 + 1)
B(x3 + 1)(x6 + 1)
C(x + 1)(x2 - x + 1)(x3-1)2
D(x + 1)3(x2 - x + 1)3
E (x3 + 1)(x6 - x3 + 1)
F cannot be factored
2x9 + 16
A 2(x - 2)(x8 - 2x4 + 4)
B2(x3 - 2)(x6 - 2x3 + 2)
C(2x3 + 2)(x6 - 2x3 - 4)
D2(x3 + 2)(x6 - 2x3 + 4)
E 2x3(x6 + 2x3 + 4)
F cannot be factored
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
'(
x^9 + 1
Can be factored as the "sum of cubes" which is x^3 + y^3 = (x + y)(x^2- xy + y^2)
so we have
x^9 + 1 = (x^3 + 1)(x^6 - x^3 + 1)
:
2x^9 + 16
Factor out 2, then factor as the sum of cubes
2(x^9 + 8) = 2(x^3 + 2)(x^6 - 2x^3 + 4)
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