SOLUTION: 2x+3y=40 and 2x+2y=20?

Question 76460: 2x+3y=40 and 2x+2y=20?
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
The given equations are:

2x + 3y = 40 -----------(1)

2x + 2y = 20 -----------(2)

Subtracting EQN (1) from (2), we get:

y = 20

Substituing this in any one of the equations, we get:

2x + 2(20) = 20

2x + 40 = 20

2x = 20 - 40

2x = -20

x = - 20/2

x = -10

Hence, the values of x = -10 and y = 20 satisfies both of the equations.

Hence, the solution.

RELATED QUESTIONS
how do I solve the system of equations: 2x+3y=40 and... (answered by jim_thompson5910)

2x = 2y + 40 3y = 72 -... (answered by Fombitz)

Solve the following system of equations algebraically and check: 2x + 3y = 11 5x - 2y (answered by jim_thompson5910)

Solve by elimination method: 3x-2y=20 and... (answered by stanbon)

2x + 3y = 8 and 3x + 2y = 7 (answered by Ratman99,jim_thompson5910)

Elimination -2X-3y=5... (answered by Boreal)

20+4y=2x+40 (answered by oberobic)

my question is 2x - 3y =5 and 3x - 2y = 20 please help me in to solve this (answered by ikleyn)

Can you put these into y=mx+b x-y=0 5x-3y=10 and x-2y=1 5x-4y= -23 and... (answered by Alan3354,stanbon)