SOLUTION: Solve for x 3^(x+4)=27^(2x)

Algebra.Com
Question 763120: Solve for x
3^(x+4)=27^(2x)

Found 3 solutions by Polyhymnio, MathLover1, DrBeeee:
Answer by Polyhymnio(2)   (Show Source): You can put this solution on YOUR website!
Since 27 = 3^3, we can rewrite the equation as
3^(x + 4) = 3^(6x)
Then take base 3 logarithms of both sides
x + 4 = 6x
5x = 4
x = 4/5

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

.......since , we have

...if bases equal then exponents have to be equal too
so, we will have
...solve for



Answer by DrBeeee(684)   (Show Source): You can put this solution on YOUR website!
Given
(1)
Now we know that
(2) and apply the rule that when we raise a power by an exponent, we multiply the exponents.
For example,
(3)
In our case we have
(4) or
(5) or
(6)
Now the powers have equal bases on the both sides of (6), so we can equate the exponents and get
(7) x + 4 = 6x or
(8) x = 4/5

RELATED QUESTIONS

Solve equation for x.... (answered by nerdybill)
solve algebraically for x: log base 27... (answered by edjones)
solve for x. log[-27]-3 =... (answered by unlockmath)
Solve for x:... (answered by scott8148)
Solve for x where x is a real number 27^2x =... (answered by stanbon)
Solve for x in the following. A) 3^x=27 B) 16^x=64 C) 2=(1/32)^x D)... (answered by MathLover1)
How do I solve for x? 27 - 2(3-2x) = 26 +... (answered by jim_thompson5910)
27^(2x+4)=(1/9)^(x-46) Please solve for... (answered by jsmallt9)
{{{ (Log( x, x^4 ) - Log( 3, 27 )) / (Log( .01 ) + Log( 4, 2 )) }}} Solve for... (answered by stanbon)