SOLUTION: how to solve
(x-3)/5 - (x+3)/2 = 6
Algebra.Com
Question 760409: how to solve
(x-3)/5 - (x+3)/2 = 6
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Given:
(1) (x-3)/5 - (x+3)/2 = 6
Multiply both sides of (1) by 10 and get
(2) 10*(x-3)/5 - 10*(x+3)/2 = 10*6 or
(3) 2*(x-3) - 5*(x+3) = 60 or
(4) 2*x -6 - 5*x - 15 = 60 or
(5) -3*x - 21 = 60 or
(6) -3*x = 81 or
(7) x = -27
Let's check this using (1).
Is ((-27-3)/5 - (-27+3)/2 = 6)?
Is (-30/5 - (-24/2) = 6)?
Is (-6 + 12 = 6)?
Is (6 = 6)? Yes
Answer: The solution to the given equation is x = -27.
Comment: The most common error is to have +15 in (4).
RELATED QUESTIONS
how to solve 1/2 + (2/3 + 3/4)-(4/3 x 5/6)
(answered by Fombitz)
how to solve... (answered by jim_thompson5910)
How do I solve for X?
(x+2)/3 - (x - 3)/2=5/6
(answered by lekelly)
how to solve x/3=x+2/5
(answered by jim_thompson5910)
how to solve x / 3 + x / 2 >... (answered by Tatiana_Stebko)
Solve and check for x.
{{{5/(x+6)+2/(x^2+7x+6)=3/(x+1)}}}
Could someone show me how to... (answered by ankor@dixie-net.com)
solve... (answered by rapaljer)
(3/8)x+2=x+(5/6)...solve for... (answered by mbmodak)
6 + (x–5)/2 = (x–7)/3
solve for... (answered by TimothyLamb)