SOLUTION: Completing the square x^2-2x-8=0
Im stuck on this thanks!
Algebra.Com
Question 750565: Completing the square x^2-2x-8=0
Im stuck on this thanks!
Found 3 solutions by FrankM, MathLover1, lwsshak3:
Answer by FrankM(1040) (Show Source): You can put this solution on YOUR website!
x^2-2x-8=0
x^2-2x+1-1-8=0
x^2-2x+1=9
(x-1)^2=9
x-1 = -3 x-1 = 3
x=-2 x=4
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
....write as
....group
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Completing the square x^2-2x-8=0
x^2-2x-8=0
(x^2-2x+1)-1-8=0
(x-1)^2=9
x-1=±√9
x=1±3
RELATED QUESTIONS
Solve by completing the square.
x^2 + 2x – 8 = 0
(answered by jim_thompson5910)
x^2+2x-11=0 ??
solve each equation by completing the square thanks for the help... (answered by lwsshak3)
x^2+2x-11=0 ???
solve each equation by completing the square thanks for your... (answered by Alan3354)
I need help completing the square of this quadratic equation. Thanks.
x^2 + 16x =... (answered by Alan3354)
Solve the quadratic equation by completing the square:
2x^2 + 10x + 11 = 0
Can... (answered by uma)
solve by completing the square:... (answered by jim_thompson5910)
solve by completing the square:... (answered by ankor@dixie-net.com)
Solve by completing the square:
x^2 + 2x - 24 =... (answered by oscargut)
Solve by completing the square... (answered by fractalier,unlockmath)