SOLUTION: How do i solve (x+1)/3 = 2/(2x-1) I know it has to be something like: (x+1)(2x-1)=3x2 (x+1)(2x-1)=6 but i don't know how to solve it after that. Thank you!

Question 750081: How do i solve
(x+1)/3 = 2/(2x-1)
I know it has to be something like:
(x+1)(2x-1)=3x2
(x+1)(2x-1)=6
but i don't know how to solve it after that.
Thank you!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do i solve
(x+1)/3 = 2/(2x-1)
I know it has to be something like:
(x+1)(2x-1)=3x2 Use * for multiply. x is taken
(x+1)(2x-1)=6
-------
2x^2 + x - 1 = 5
2x^2 + x - 6 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=49 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1.5, -2. Here's your graph:

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