SOLUTION: The equation for voltage dividers in electronics stated in basic algebraic terms is:
x=y(b/(a+b))
As a and b represent resistor values I have the equations to solve for each of t
Algebra.Com
Question 747270: The equation for voltage dividers in electronics stated in basic algebraic terms is:
x=y(b/(a+b))
As a and b represent resistor values I have the equations to solve for each of them. I have been able to figure out the steps to calculate for a, however, the steps to arrive at the formula for b has eluded me. The formula given is:
b=(xa)/(y-x)
I suppose I could just memorize the formula but I think I must be missing something very basic that I cannot work out the steps myself. Your help would be much appreciated. Glenn
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
we need to solve
x=y(b/(a+b)) for b
divide both sides of = by y
x/y = b/(a+b)
cross multiply the two fractions and we get
x(a+b) = yb
xa+xb = yb
now group the terms with b on to same side of = sign
yb-xb = xa
factor out the b
b(y-x) = xa and
b = xa/(y-x)
RELATED QUESTIONS
An electronics store sells an item costing $51 for $70 and an item costing $120 for $129. (answered by Theo)
In electronics, according to Ohm's law, E = IR, where "E" is
voltage (measured in... (answered by Alan3354)
In electronics, according to Ohm's law, E = IR, where "E" is
voltage (measured in... (answered by ikleyn,Alan3354)
An equation that defines y as a function of x is given. Complete parts a and b.
5x-3y=1
(answered by stanbon)
The circles in the diagram are concentric. Write an algebraic expression for c in terms... (answered by ikleyn)
If y=a/a+b and x=a/b, what is y in terms of... (answered by jim_thompson5910)
A 10-ohm resistor is used to test the voltage in two different circuits. Circuit A shows... (answered by Alan3354)
1. Solve the equation below for d, in terms of a,b,and c.
a/b = c/d
2. Solve the... (answered by Osran_Shri)
Name the algebraic property demonstrated in the example below.
If a = x and x = b, then... (answered by stanbon)