SOLUTION: 4x2y/2xy3= The 2 after the x is squared. The 3 after the y is cubed. I tried listening in class but it's not clicking. I need some big help! Thankyou.

Question 74361This question is from textbook Addison-Wesley Algebra
: 4x2y/2xy3=
The 2 after the x is squared. The 3 after the y is cubed. I tried listening in class but it's not clicking. I need some big help! Thankyou. This question is from textbook Addison-Wesley Algebra

Found 2 solutions by checkley75, jim_thompson5910:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
IT'S BEST TO BREAK THESE DOWN TO THE COMMON ITEMS AS FRACTIONS & REDUCE EACH INDIVIDUALLY.
4X^2Y/2XY^3
4/2=2
X^2/X=X
Y/Y^3=1/Y^2 NOW COMBINE THE INDIVIDUAL ELEMENTS THUS:
2X/Y^2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

When dividing like bases with exponents we subtract the exponents. If I have it translates to or . So we're going to apply the same idea for this problem.

Simplify 4/2 to 2
When we have negative exponents, we invert the base (ie because if we have . So

Here's the simplified form.
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