SOLUTION: If (a+b)^2 + (b+c)^2 + (c+d)^2 = 4(ab+bc+cd), prove a=b=c=d

SOLUTION: If (a+b)^2 + (b+c)^2 + (c+d)^2 = 4(ab+bc+cd), prove a=b=c=d

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Question 742010: If (a+b)^2 + (b+c)^2 + (c+d)^2 = 4(ab+bc+cd), prove a=b=c=d
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

so (a-b)^2=0
a-b=0
a=b
similarly b=c
c=d
a=b=c=d
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