SOLUTION: how can i write the equation of a line that passes throught (-2,-1) and is perpendicular to x-2y=6?
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Question 733450: how can i write the equation of a line that passes throught (-2,-1) and is perpendicular to x-2y=6?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how can i write the equation of a line that passes throught (-2,-1) and is perpendicular to x-2y=6?
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Find slope of the given line:
2y = x-6
y = (1/2)x - 3
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Slope = 1/2
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Slope of perpendicular line must be -2
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Form: y = mx + b
Solve for "b":
-1 = -2*-2+b
b = -5
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Equation:
y = -2x-5
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Cheers,
Stan H.
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