SOLUTION: You helped me and I am stuck again. Sorry. I do not understand how I can rearrange factors. I tried the info you gave before but cannot get these two. Factor:
-6x^2 +13x -2
-5x^2
Algebra.Com
Question 733364: You helped me and I am stuck again. Sorry. I do not understand how I can rearrange factors. I tried the info you gave before but cannot get these two. Factor:
-6x^2 +13x -2
-5x^2 +x +18
Thank you so much.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If the lead coefficient is negative, first take -1 out.
Multiply the lead coefficient by the constant term: 6 times 2 is 12.
List the possible factor pairs for the product of the lead coefficient and the constant term:
1 and 12
2 and 6
3 and 4
-1 and -12
-2 and -6
-3 and -4
Add each of the pairs to see if you can find a sum that is equal to the 1st degree term, -13 in this case. -1 and -12 works. Split the 1st degree term:
Divide the polynomial into the sum of two binomials.
Factor any common factors from each of the binomials:
Factor out the binomials:
Do the other one the same way.
John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
I am wondering if anyone can help me, the last tutor that helped (Alan3354) did not help... (answered by Earlsdon)
Hello. I am sorry for the bother, but please help me. During the summer, I must study... (answered by jim_thompson5910)
Can you please help me to solve this equation. I have tried but am getting frustrated. I... (answered by lwsshak3)
Hello,
I am a student who is in Grade 11 and in Mathematics Grade 11 Foundations. We... (answered by mouk)
Y=2/3x and Y=-2/7x+4/7
I am not even sure how to set this up. Do I need to have the... (answered by phillv)
Hello,
I am trying to graph the following but I been out of school for 15 years can... (answered by stanbon)
I know how to do graphs but I do not know how to do slopes could someone help me please.
(answered by jim_thompson5910)
I do not understand how you do this problem can you please help. Thank you
Four times... (answered by mananth,ankor@dixie-net.com)
Hi there,I'm new so im sorry if i do not do something correctly. I am too embarrassed to... (answered by stanbon,jim_thompson5910)