SOLUTION: How do you put the following word problem into two equations: A collection of dimes and quarters totals $9.90. There are six more quarters than dimes. How many of each coin are the
Algebra.Com
Question 731645: How do you put the following word problem into two equations: A collection of dimes and quarters totals $9.90. There are six more quarters than dimes. How many of each coin are there?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let d = no. of dimes
let q = no. or quarters
:
Write an equation for each statement:
:
"A collection of dimes and quarters totals $9.90."
.01d + .25q = 9.90
:
There are six more quarters than dimes.
q = d + 6
:
Now you can substitute (d+6) for q in the first equation
then solve for d
:
Then q = 6 more than that solution
:
Check your solutions in the 1st equation
RELATED QUESTIONS
could you show me how to set up these equations?? Thanks word problem. the sum of two... (answered by mananth)
How Do i Solve THe following Equation?
Translate to a system of equations and solve.... (answered by solver91311)
could you show me how to set this problem up. A collection of nickels, dimes and quarters (answered by mananth)
Two thirds of the coins in a collection of quarters and dimes are quarters. The... (answered by MathTherapy)
In a collection of dimes and nickels there are 43 coins. all together the cost is $3.05.... (answered by josmiceli)
I need some help with this word problem.
A collection of 43 coins consists of dimes... (answered by nerdybill)
A coin collection has 18 coins consisting of quarters and dimes. There are two more dimes (answered by macston)
A coin collection has 22 coins consisting of quarters and dimes. There are two more dimes (answered by lynnlo)
A collection of nickels, dimes and quarters is worth $5.30. There are two more dimes... (answered by ikleyn)