SOLUTION: Take the graph of y=2^x and transform it into y= -3(2)^(2x-4). Label 3 key points on both graphs. I've tried graphing it and applying the required stretches and transformations

Question 724219: Take the graph of y=2^x and transform it into y= -3(2)^(2x-4). Label 3 key points on both graphs.
I've tried graphing it and applying the required stretches and transformations (vertical stretch by 3, horizontal stretch by 1/2, reflection on x-axis, horizontal translation 4 units left) but my graph doesn't match the graph I plug into the calculator. Am I doing something wrong?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Assuming you meant y equals x squared (y=x^2):
To transform into
you need a horizontal translation by 2 units right,
because you replaced by and then by .
A little algebra to get a simplified formula for the same function could have helped:
--> --> --> -->
Then you would need a vertical stretch by 12, reflection on x-axis, and horizontal translation 2 units right.

NOTE: If you meant and
the same thing applies.
puts 2 units to the left by subtracting 4, but
in the compound function , to get the same y value you need to add 4 to x:

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