SOLUTION: How do you solve these two equations using the quadratic formula? 2x^2-7x=-5....How do I get an A,B,and C if there is only A and B? 6x^2=2x+1....Do I switch this around to make

Question 713868: How do you solve these two equations using the quadratic formula?
2x^2-7x=-5....How do I get an A,B,and C if there is only A and B?
6x^2=2x+1....Do I switch this around to make A, B and C?
Answer by BGutridge(15) (Show Source): You can put this solution on YOUR website!
1) 2x^2-7x=-5 Set the equation equal to zero. That leaves 2x^2-7x+5=0. Then

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=9 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.5, 1. Here's your graph:

2) 6x^2=2x+1 Set the equation equal to zero, which gives 6x^2-2x-1=0. Then

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=28 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.607625218510765, -0.274291885177432. Here's your graph:

Sorry that that 2nd one doesn't have a simple answer.
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