SOLUTION: How do I solve this problem? x^3+3x^3-4x-12=0

Question 711404: How do I solve this problem?
x^3+3x^3-4x-12=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I solve this problem?
x^3+3x^2-4x-12=0
--------
I graphed the cubic and found a root at x = -2
---
Use synthetic division to find the other zeroes:
-2)....1....3....-4....-12
.......1....1....-6...|..0
Quotient: x^2 + x -6
---
Solve x^2 + x -6 = 0
Factor:(x+3)(x-2) = 0
Zeroes: x = -2, x = 2, x = -3
==============================
Cheers,
Stan H.
==============================
RELATED QUESTIONS
x^2+4x+3=0, how do i solve... (answered by jim_thompson5910)

How do I solve this problem? Multiply. (4x+7)(2x^2+3x+3) thank... (answered by aib31180)

How would I solve this problem? {{{ (3x+7)^(1/3)-(4x+2)^(1/3)=0... (answered by jim_thompson5910)

#1) (2x-3) (4x+5)=0 #2) X to the second power -3x=0 How do I solve this? (answered by stanbon)

how do I solve... (answered by deborabr)

how do i solve this math problem. 3x + 6= x+12 do i figure it out like this... (answered by Alan3354)

solve 3x�+6x+3=0 how do i solve... (answered by swincher4391)

how do i solve for x with this? 12 + x 4x-14 _______ = _______ + 4 −4 (answered by josgarithmetic)

(3/x)^-3 how do I solve this problem? (answered by ankor@dixie-net.com)