SOLUTION: Hi, I keep trying to figure out where I am going wrong in this equation but I cannot. The equation is... a=b a^2=ab a^2-b^2=ab-b^2 (a+b)(a-b)=b(a-b) a+b=b a+a=a 2a=a 2=1

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Question 710207: Hi,
I keep trying to figure out where I am going wrong in this equation but I cannot. The equation is...
a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
a=b
 a^2=ab
 a^2-b^2=ab-b^2
 (a+b)(a-b)=b(a-b)
 a+b=b   <-- this step is wrong because you can only divide both
             sides by a number other than zero, however the first
             step is a=b which means that a-b = 0, so this step
             is incorrect because it divides the preceding step
             through by zero.   

Edwin

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