# SOLUTION: Not in book. Jim's brakes charges \$25 for parts and \$55 per hour to fix the brakes on a car. Myron's Auto charges \$40 for parts and \$30 per hour to do the same job. What length

Algebra ->  Algebra  -> Equations -> SOLUTION: Not in book. Jim's brakes charges \$25 for parts and \$55 per hour to fix the brakes on a car. Myron's Auto charges \$40 for parts and \$30 per hour to do the same job. What length       Log On

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 Click here to see ALL problems on Equations Question 70989: Not in book. Jim's brakes charges \$25 for parts and \$55 per hour to fix the brakes on a car. Myron's Auto charges \$40 for parts and \$30 per hour to do the same job. What length of job in hours would have the smae cost of both shops? Thank you for helping me. I hate written problemsAnswer by jim_thompson5910(28598)   (Show Source): You can put this solution on YOUR website!For Jim's brakes use the equation: and for Myron use To find out when they will cost the same, set the two equations equal to each other (in other words set the two unknown prices equal to each other) Solve for x (the time) So at 3/5 of an hour or at 36 minutes they will cost the same