SOLUTION: Not in book. Jim's brakes charges $25 for parts and $55 per hour to fix the brakes on a car. Myron's Auto charges $40 for parts and $30 per hour to do the same job. What length

Algebra ->  Algebra  -> Equations -> SOLUTION: Not in book. Jim's brakes charges $25 for parts and $55 per hour to fix the brakes on a car. Myron's Auto charges $40 for parts and $30 per hour to do the same job. What length       Log On

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Question 70989: Not in book.
Jim's brakes charges $25 for parts and $55 per hour to fix the brakes on a car. Myron's Auto charges $40 for parts and $30 per hour to do the same job. What length of job in hours would have the smae cost of both shops?
Thank you for helping me. I hate written problems
Answer by jim_thompson5910(28598) About Me  (Show Source):
You can put this solution on YOUR website!
For Jim's brakes use the equation: y=25%2B55x and for Myron use y=40%2B30x
To find out when they will cost the same, set the two equations equal to each other (in other words set the two unknown prices equal to each other)
25%2B55x=40%2B30xSolve for x (the time)
25x=15
x=15%2F25
x=3%2F5So at 3/5 of an hour or at 36 minutes they will cost the same