SOLUTION: how would i solve for m the equation 2m^3=54, i am guessing it should start off with 2m^3-54=0 then, 2(m^3)=2(-27)=0, but then i get totaly lost and confused any help please

Question 709161: how would i solve for m the equation 2m^3=54, i am guessing it should start off with 2m^3-54=0 then, 2(m^3)=2(-27)=0, but then i get totaly lost and confused any help please
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
2m^3=54
divide both sides by 2:
m^3=27
take the "cube root" of both sides:
m = cubeRt(27)
factor to prime numbers:
m = cubeRt(3*3*3)
m = 3
RELATED QUESTIONS
The directions say: Solve the equation. Check your solution. {{{2m/(m+4) = 3/(m-1)}}} (answered by stanbon,josmiceli)

44. m^3+2m^2-3m=0 (answered by stanbon,hayek)

m^3+2m^2-3m=0 (answered by jim_thompson5910)

M^2+2M=3 (answered by zoomkaboom4)