SOLUTION: Solve the equation. Identify any extraneous solutions. x=√(x+30)
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Question 705192: Solve the equation. Identify any extraneous solutions. x=√(x+30)
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Original equation, x=√(x+30).
Square both sides: x^2=x+30. Adjust into general form:
x^2-x-30=0
Factor it? (x-6)(x+5)=0.
Solutions possible are x=+6 or x=-5. One of these may be "extraneous" and will not work in the original equation of x=√(x+30).
Check +6:
6=sqrt(6+30)? Yes. Because 6*6=36.
Check -5:
5=sqrt(-5+30)? 5=sqrt(+25)? Yes. This too works.
Solution is then or .
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