SOLUTION: when the shot is releases at an angle of 65 degrees, its path can be modeled by the formula y=-0.04xsquared+2.1x+6.1, in which x is the shots horizontal distance, in feet, and y i

Question 704601: when the shot is releases at an angle of 65 degrees, its path can be modeled by the formula
y=-0.04xsquared+2.1x+6.1, in which x is the shots horizontal distance, in feet, and y is its height, in feet. use the formula to determine the shots maximum distance and round to the nearest tenth of a foot
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
when the shot is releases at an angle of 65 degrees, its path can be modeled by the formula y=-0.04xsquared+2.1x+6.1, in which x is the shots horizontal distance, in feet, and y is its height, in feet. use the formula to determine the shots maximum distance and round to the nearest tenth of a foot
y=-0.04xsquared+2.1x+6.1
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When the shot hits the ground its height will be zero.
Solve:
-0.04x^2 + 2.1x + 6.1 = 0
Use the Quadratic Formula:
x = [-2.1 +- sqrt(2.1^2 - 4*-0.04*6.1)]/(2*-0.04)
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x = [-2.1 +- sqrt(5.386)]/(-0.08)
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x = [-2.1 - 2.3201]/-0.08
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x = 55.26 ft
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Cheers,
Stan H.
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