SOLUTION: Find the axis of symmetry: y = x^2 - x + 10 I can not seem to understand this method, I did look back at some other ones, but felt it confused me even more, help please, thank

Question 70366: Find the axis of symmetry:
y = x^2 - x + 10
I can not seem to understand this method, I did look back at some other ones, but felt it confused me even more, help please, thank you!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the axis of symmetry:
y = x^2 - x + 10
Rewrite as follows:
x^2-x+10 = y
Set it up for completing the square:
x^2-x+? = y-10+?
Complete the square and keep the equation balanced.
x^2-x+(1/2)^2 = y-10+(1/2)^2
Factor the left side and simplify the right to get:
(x-(1/2))^2 = y-(39/4)
The vertex is at (1/2,(39/4))
So the axis of symmetry is x=(1/2)
Cheers,
Stan H.
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