SOLUTION: q^2+6q-7=0
Algebra.Com
Question 702894: q^2+6q-7=0
Answer by jpvn2015(54) (Show Source): You can put this solution on YOUR website!
q^2 + 6q = 7
q = 1
It is pretty intuitive when you look at it.
Check: 1^2 + 6 = 7
1+6 = 7
7=7
CHECK!
RELATED QUESTIONS
Please help! I am really stuck... (answered by Alan3354)
Find all real/imaginary solutions to
q^2+6q-7=0
(answered by Fombitz)
-5/6q-(q-1/2)=1/4(q+1) (answered by jim_thompson5910)
p^8q^7/p^6q^2 (answered by jim_thompson5910)
6q-(q-3)=2q+3(q+1) (answered by jim_thompson5910)
6q^2+4q-2 (answered by checkley75)
find the positive roots for 12q + 5 = (6q^2 +5q+59) / q
(answered by Fombitz)
(2p-5q)+(3p+6q)+(p-q) (answered by checkley77)
Solve for q |-6q+9| <... (answered by josgarithmetic,ikleyn,MathTherapy)