SOLUTION: Could you please help me with the following? Solve for x in {{{1-x-(2/(6x+1))=0}}}. My working is.. {{{2=(6x+1)(1-x)=6x^2+5x+1}}} {{{6x^2+5x-1=0}}} Into the quadratic formu

Question 696806: Could you please help me with the following?
Solve for x in . My working is..

Into the quadratic formula...

or
The correct answer is x=1/3, x=1/2?
Thanks.

Found 2 solutions by god2012, MathTherapy:
Answer by god2012(113) (Show Source): You can put this solution on YOUR website!

Can be reduced to {6x^2 - 5x +1 } = 0
6x^2 - 3x - 2x + 1 = 0
{3x ( 2x - 1 ) - 1(2x - 1 )} = 0
{{(2x - 1) (3x - 1) } = 0}
{2x - 1 } = 0 OR {3x - 1 } = 0.
{ X = {(1/2) or (1/3)}}

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Could you please help me with the following?
Solve for x in . My working is..

Into the quadratic formula...

or
The correct answer is x=1/3, x=1/2?
Thanks.

** Note that

1(6x + 1) - x(6x + 1) - 2 = 0(6x + 1) ----- Multiplying by LCD, 6x + 1

, or

You can now solve for x. Notice that the equation is different from yours!!

You can then do the check!!

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