SOLUTION: Arnold had $1.70 in dimes and quarters. HE had 3 more dimes than quarter. How many of each coin did he have?

Question 69542: Arnold had $1.70 in dimes and quarters. HE had 3 more dimes than quarter. How many of each coin did he have?
Answer by tanimachatterjee(60) (Show Source): You can put this solution on YOUR website!
suppose Arnold had x dimes and y quarters
value of x dimes = 10x cents
y quarters =25y cents
tolal value =10x+25y cents
by the problem 10x+ 25y=170..............(1)
and x=y+3....(2)
replacing the value of x in (1) we have 10(y+3) +25y=170
or 10y +30 +25y=170
or 35y= 170-30=140
y= 4
x=y+3
= 4+3
=7
Arnold had 7 dimes and 4 quarters

RELATED QUESTIONS
Arnold had $1.70 in dimes and quarters. He had 3 more dimes than quarters. How man of... (answered by macston,addingup)

He had a total of 5.35 in dimes and quarter. He has 6 more quarters than dimes. How many... (answered by Alan3354)

Reggie's younger brother had several coins when he returned from his paper route. He has... (answered by macston)

We need to Write the equation. Arnold had $1.70 in dimes and quarters. He had 3 more... (answered by checkley71)

Gerald had $1.70 in dimes and quaters. He had 3 more dimes than quaters. How's many of... (answered by swincher4391)

If Brad had $25.65 in quarters and dimes his money jar, but he had 20 more quarters than... (answered by mananth)

Joe saved a number of nickels,dimes, and quarters. He had 3 more dimes than nickels. He... (answered by MathLover1)

Angel was counting the coins in his bank. He found that he had 70 coins, which totaled... (answered by Edwin McCravy,Cromlix)

Craig has 38 quarters and dimes. If he had twice as many quarter, he would have $11. How... (answered by josmiceli)