SOLUTION: Please help me with Motion Problems- A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the

Question 68955: Please help me with Motion Problems-
A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
I don't know how to solve it exactly. Thank you for your time.
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
:
We know when they meet they will have traveled a total of 388 miles, and both will have traveled for 4 hours.
:
Let s = speed of the train from G.C.
:
Dist = time * speed
:
Belleville train dist + G.C train dist = 388 mi
4(47) + 4s = 388
188 + 4s = 388
4s = 388 - 188
4s = 200
s = 200/4
s = 50 mph speed of train from G.C.
:
:
Check 4(47) + 4(50) = 388

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

The train from Belleville has travelled a distance of

mi
That means the other train has travelled mi in 4 hrs
mi

mi/hr answer
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