SOLUTION: Find the equation of the line passing through the given point and perpendicular to the equation of the line. (-2,3) ; 5x-4y-6=0

Question 684046: Find the equation of the line passing through the given point and perpendicular to the equation of the line. (-2,3) ; 5x-4y-6=0
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
Start with 5x-4y-6=0
5x-6 = 4y
y =
has a slope of
A perpendicular line will have a negative inverse/reciprocal slope of
...
Use the slope and the point (-2, 3) in the point-slope formula
y - 3 = (x--2)
y - 3 = (x+2)
y - 3 =
y - 3 =
y =
y =
y =
...

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