SOLUTION: find 3 consecutive intergers whose sum is -33
Algebra.Com
Question 678545: find 3 consecutive intergers whose sum is -33
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
x+(x+1)+(x+2) = -33
3x+3 = -33
3x = -33-3
3x = -36
x = -36/3
x = -12
x+1 = -11
x+2 = -10
So the three consecutive integers are -12, -11, -10
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